Answer:

description	start at 1, count upward by 2's, quite when count exceeds 10
sequence	1 3 5 7 9
code	`for ( count= 1 ; count < 10; count+=2 )`

Counting by Threes

Here is almost the same loop as in the previous example, but now the control variable is incremented by THREE.

int count;
for ( count = 0; count <= 12; count += 3 )  
{
  System.out.println( "count is: " + count ); 
}
System.out.println( "/nDone with the loop./nCount is now" + count);

Here is a JavaScript version of this loop. Try to predict the output before you run the program. (Notice that the test is now <= ).

QUESTION 8:

Now show the for statement for each of the following sequences

start at 0, count upward by 1's, end at 7	for ( count = ___; count < ___; count++ )
start at 0, count upward by 2's, end at 14	for ( count = ___; count < ___; count += 2 )	start at 1, count upward by 2's, end at 15	for ( count = ___; count < ___; count += 2 )