Answer:
No. The reference in source
will be copied into target,
but this will have no effect on the actual arrays
because source and target are
formal parameters of copy().
The variables s and t of the
main program will not be changed,
nor will any array element be changed.
End of the Chapter
That about wraps it up for this chapter. You may wish to review the following. Click on a subject that interests you to go to where it was discussed.
- Call by value.
- Picture of an array used as a parameter.
- Step-by-step description of call by value with an array.
- ZeroAll() method.
- ArrayCopy() method.
You have reached the end of the chapter.