Answer:

The catch{} blocks are in a correct order, because ArithmeticException is not an ancestor nor a descendant of InputMismatchException. Reversing the order of the two blocks would also work.

Possible Exceptions

In the example program, the try{} block might throw a NumberFormatException, or an ArithmeticException.

  public static void main ( String[] a ) 
     . . . .

    try
    {
      System.out.print("Enter the numerator: ");
      num = scan.nextInt();
      System.out.print("Enter the divisor  : ");
      div = scan.nextInt();
      System.out.println( num + " / " + div + " is " + (num/div) + " rem " + (num%div) );
    }
    catch (InputMismatchException ex )
    {
      . . .
    }

    catch (ArithmeticException ex )
    {
      . . .
    }
  }

A NumberFormatException might occur in either call to nextInt(). The first catch{} block is for this type of Exception.

An ArithmeticException might occur if the user enters data that can't be used in an integer division. The second a catch{} block is for this type of Exception.

QUESTION 13:

What type of Exception is thrown if the user enters a 0 for the divisor?